10x-3=(x^2+8x)+(8x+64)

Solution for 10x-3=(x^2+8x)+(8x+64) equation:

10x-3=(x^2+8x)+(8x+64)

We move all terms to the left:

10x-3-((x^2+8x)+(8x+64))=0


We calculate terms in parentheses: -((x^2+8x)+(8x+64)), so:

(x^2+8x)+(8x+64)

We get rid of parentheses

x^2+8x+8x+64

We add all the numbers together, and all the variables

x^2+16x+64

Back to the equation:

-(x^2+16x+64)


We get rid of parentheses

-x^2+10x-16x-64-3=0

We add all the numbers together, and all the variables

-1x^2-6x-67=0

a = -1; b = -6; c = -67;
Δ = b2-4ac
Δ = -62-4·(-1)·(-67)
Δ = -232
Delta is less than zero, so there is no solution for the equation